Question
Calculate the concentration of oxalate ion (c2o42–) in a 0.175 m solution of oxalic acid (c2h2o4). [for oxalic acid, ka1 = 6.5 × 10–2, ka2 = 6.1 × 10–5.]
Asked by: USER7274
153 Viewed
153 Answers
Responsive Ad After Question
Answer (153)
C2H2O4 C2HO4- + H+
0.175 - x x x + y
C2HO4- c2o42– + H+
x - y y x + y
K2 = (y) (x +y) / (x-y)
As, y << x
So, K2 = (y) (x) / (x)
K2 = y =6.1 × 10^–5
Hence, concentration of (c2o42–) 6.1 × 10^–5 M