Question
A reaction has a standard free-energy change of –10.90 kj mol–1 (–2.605 kcal mol–1). Calculate the equilibrium constant for the reaction at 25 °c.
Asked by: USER2942
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Answer (146)
The relation between free energy change and equilibrium constant is
ΔG = -RT ln Keq
T = 298 K
R = 8.314 J / mol K
Keq = ?
ΔG = -10.90 kJ / mole
ΔG = - 8.314 X 298 X ln Keq
ln Keq = 10900 / 8.314 X 298 = 4.4
Keq = 81.45