Question
Bonjour, aidez moi s il vous plaît Développez M = (3x-7)^2-(3x-7)(2x-1)+(6x-14)
Asked by: USER3814
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Answer (92)
Réponse :
bonsoir
Explications étape par étape
(3x-7)²-(3x-7)(2x-1)+(6x-14)=
9x² -42x+49-(6x²-3x-14x+7)+(6x-14)=
9x²-42x+49-6x²+3x+14x-7+6x-14=
3x² -19x+28
Bonjour,
[tex](3x - 7) {}^{2} - (3x - 7)(2x - 1) + 6x - 14[/tex]
= 9x^2 -42x +49 - (6x^2 -3x -14x +7) +6x -14
= 9x^2 -42x +49 -6x^2 +3x +14x -7 +6x -14
= 3x^2 -19x +28
[tex](3x - 7) {}^{2} - (3x - 7)(2x - 1) + 6x - 14[/tex]
= 9x^2 -42x +49 - (6x^2 -3x -14x +7) +6x -14
= 9x^2 -42x +49 -6x^2 +3x +14x -7 +6x -14
= 3x^2 -19x +28