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#3sin3x+cos3x=2

#=racines 

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Grade: Education Subject: mathematiques

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#3sin3x+cos3x=2

#=racines 

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cela donne (V3/2)sin(3x)+(1/2)cos(3x)=1

 

or (V3/2)sin(3x)+(1/2)cos(3x) c'est cos(pi/6)sin(3x)+sin(pi/6)cos(3x) soit sin(3x+pi/6)

 

l'équation est donc sin(3x+pi/6)=sin(pi/2)

 

donc 3x+pi/6=pi/2 +2kpi finalement x=pi/9+2kpi/3