Pertanyaan
Sebanyak 600 ml larutan CH3COOH 0,1 M , Di campurka dengan 600 ml CH3COONa 0,15 M (ka CH3COOH = 1,8 × 10^-5). Tentukan PH campuran tsb
Ditanyakan oleh: USER8518
134 Dilihat
134 Jawaban
Responsive Ad After Question
Jawaban (134)
jumlah mol CH3COOH = M x V = 0,1 x 600 = 60 mmol
jumlah mol CH3COOHNa = M x V = 0,15 x 600 = 90 mmol
[H+] = ka x a/g
= 1,8.10^-5 x 60/90
= 1,2 . 10^-5
PH = - log [H+]
= - log 1,2.10^-5
= 5 - log 1,2
Semoga membantu;))
jumlah mol CH3COOHNa = M x V = 0,15 x 600 = 90 mmol
[H+] = ka x a/g
= 1,8.10^-5 x 60/90
= 1,2 . 10^-5
PH = - log [H+]
= - log 1,2.10^-5
= 5 - log 1,2
Semoga membantu;))