diketahui segitiga ABC sama sisi dengan panjang sisi 12 cm. Panjang jari jari lingkaran dalamnya adalah?

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jari2 lingkaran dalam = L/S
L = luas segitiga
S = 1/2 keliling segitiga = (12×3) : 2 = 18 cm
a = b = c = 12 cm

luas segitiga = √s (s-a)(s-b)(s-c)
luas segitiga = √18 (18-12)(18-12)(18-12)
luas segitiga = √18 × 6 × 6 × 6
luas segitiga = √2 × 3 × 3 × 2 × 3 × 2 × 3 × 2 × 3
luas segitiga = 2 × 3 × 2 × 3 √3
luas segitiga = 36 √3

jari2 lingk. dalam = L/S = 36√3 / 18 = 2√3 cm

Dijawab pada tanggal 28 Agustus 2025

diketahui segitiga ABC sama sisi dengan panjang sisi 12 cm. Panjang jari jari lingkaran dalamnya adalah?

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Jawaban (105)

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A=2^9x3^7x5^13
B=2^25x3^8x5^11
in cate zerouri se termina produsul AxB ?

II.
Impartind un nr natural la 24 se obtine restul 14. Ce rest se obtine impartind acelasi nr la 4 ?

Se considera f:(0,∞)->R
f(x)=lnx
a) Aratati ca (p+1)[tex] \int\limits^x_1 {f ^{p}(t) } \, dt+ \int\limits^x_1 {f ^{p+1}(t) } \, dt=xf^{p+1}(x) [/tex] , ptr orice x>=1 si p>0

Ce părți de vorbire au cuvintele "este" , "cea" , "un" ?
Multumesc frumos .