dua kandang berdampingan masing masing xm dan ym. luas kandang 24 m2. Agar panjang pagar yang diperlukansesedikit mungkin, maka panjang x dan y secara berturut turut

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Grade: Education Mata Pelajaran: matematika

Ditanyakan oleh: USER2862

165 Dilihat 165 Jawaban

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Jawaban (165)

USER7615

Jawaban Terbaik

(165)

Luas persegi panjang = 12
12 terbentuk dari perkalian antara
1×12
2×6
3×4
Maka agar panjang yang dibutuhkan paling sedikit adalah 3m ×4m.

Dijawab pada tanggal 1 September 2025

dua kandang berdampingan masing masing xm dan ym. luas kandang 24 m2. Agar panjang pagar yang diperlukansesedikit mungkin, maka panjang x dan y secara berturut turut

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Jawaban (165)

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