b supra 13 × b× b supra 21 × b supra 20 VA ROG FRUMOS!!!!

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29 Agustus 2025 matematica 5 minute
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Clasă: Education Materie: matematica
b supra 13 × b× b supra 21 × b supra 20 VA ROG FRUMOS!!!!
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[(b/13•b•b)/21•b]/20=[(b^3/13)/21•b]/20=(b^3/13 • 1/21•b)/20=(b^2/21•13)/20=(b^2/273)/20=b^2/273•1/20=b^2/5460
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