Rezolvati in multimea nr.naturale ecuatia:
3·{10+2·[40-2·(28-3·5)]}-7×=51

Răspunsul a fost dat de: USER6755
30 Agustus 2025 matematica 5 minute
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Clasă: Education Materie: matematica
Rezolvati in multimea nr.naturale ecuatia:
3·{10+2·[40-2·(28-3·5)]}-7×=51
Întrebare a fost pusă de:
78 Vezi 78 Răspunsuri

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3 · {10+2 · [40-2 · (28-3·5)]} -7x = 51
=> 30+6*[40-2*(28-15)]-7x=51
      30+6*[40-2*13]-7x=51
      30+6*14-7x=51
      114-7x=51
       7x=114-51
         x=(114-51) : 7
         x=9
Răspunsul a fost dat în data 30 Agustus 2025

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